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# Textile Gate Solved papers | Tf_Gate 1992 ### 1. During length measurement of Fibrograph 2.5% span length was found to be 25mm. it means.

1. 2.5% of fibers clamped are 25mm in length.

2. 2.5% of fibers clamped are longer than 25mm.

3. 2.5% of fibers clamped are 25mm or longer.

4. 2.5% of fibers clamped are less than 25mm.

Ans: 1

### 2. The count of yarn is 20 Tex. It is equivalent to a yarn of

1. 29.5 Ne. (English Count)

2. 180 Denier.

3. 50 Nm (Metric count)

4. None of the above.

Ans: a, b, & c

Tex to Ne.

We Know that

Tex = i.e., Ne. =

Therefore, 20 Tex = = 29.525 Ne.

Tex to Denier

We know that

1 Tex = 9 Denier

Therefore, 20 Tex = 20 x 9 Denier = 180 Denier

Tex to Nm

We know that

Tex = i.e., Nm = 1000/Tex

Therefore, 20 Tex = 1000/20 = 50Nm.

### 3. The resultant count of two cotton yarns is 16s Ne. If the doubling process causes a contraction of 10% in the component yarns, the count of the component single yarn will be?

1. 35.2s Ne

2. 28.8s Ne

3. 32s Ne

4. None of the above

Ans: 1

Given that Resultant count= 16s

Let’s assume that the two single yarns are of the same count. Then the count of a single yarn is 32

As mentioned, there is a 10% contraction during the doubling

Therefore, count of single yarn = 32 + 10% contraction

= 32+ 3.2 = 35.2s

### 4. The number of thin places were detected at -30% and -50% thin place setting on a uster imperfection indicator. The incidence will be higher at

1. -30%

2. 505

3. None of the above

Ans: 1

The incidence will be more at thin places and less thin cross-section

### 5. Under CRL and CRE conditions of testing, what happens to the rate of loading when the length of the specimen is increased?

4. None of the above.

Ans: 1 & 2

### 6. with respect to tear strength which of the following statements are correct?

1. Tear strength of twill weave > Tear strength of plain weave.

2. Tear strength of high set fabric < Tear strength of the low set fabric.

3. Tear strength does not depend upon weave and set.

4. Tear strength depends upon thread strength.

Ans: 1, 2 & 4

### 7. which of the following phenomenon may be described by passion Distribution

1. The number of warp breakages on a loom.

3. The number of neps in a given area of card web.

4. The number of end breakages in ring spinning.

Ans: 3

### 8. The correct relationship between specific surface (s) and diameter (d) of a fiber can be described by

1. S = 1/d

2. S = 4/d

3. S = (perimeter of Cross-section) / (Area of Cross-section)

4. None of the above

Ans: 2 & 3

### 9. The standard error of estimate of difference of two means having a sample size of n1 and n2 and the pooled estimate of standard deviation s, is Ans: 1 & 3

### 10. Which of the following relationships is/are correct? Ans: 1 & 4

### 11. The U% of a single yarn is 17.3%. The expected CV% of a 3-ply yarn made from these single yarns would be?

1. 12.5

2. 10.0

3. 17.3

4. None of the above

Ans: 1

CV of single yarn is = 1.25 * U% = 1.25 * 17.3 = 21.625 %

CV% of 3 ply yarn = CV of single yarn / √n where n = no. of doublings

= 21.625 / √3 = 12.5%

### 12. The weight per meter of cotton sliver normally lies between

1. 500 mg and 1000 mg

2. 3g and 4g

3. 10g and 15g

4. 40g and 60g

Ans: 2

### 13. The RKm of a yarn is equal to

1. g/tex

2. g/den

3. breaking length in Km

4. CSP

Ans: 3

### 14. The number of fibers in the cross-section of a 20s cotton yarn would be approximately

1. 85

2. 170

3. 340

4. 680

Ans: 2

The average fibers in yarn cross-section are 100-200

### 15. Roller and clearer card is used for carding of

1. Cotton

2. Cotton waste

3. Wool

Ans: 2 & 3

### 16. Sectional warping is considered more practical than beam warping

1. For executing big orders.

2. For producing striped fabrics.

3. When sizing is considered necessary.

4. When the two-fold yarn has to be used in warp and weft

Ans: 2

### 17. Sizing gives to the yarn

1. Higher breaking strength

2. Increased elongation at break

3. Increased pliability

4. None of the above

Ans: 1

### 18. 1kg of 20 Ne will have a length of

1. 16,800 yards

2. 33,600 meters

3. 20,000 meters

4. 16,800 meters

Ans: 2

We know that

Ne = (Length in yards) / (840 x weight in pounds)

1 kg = 2.2046 lbs

20 = length / 840 x 2.2046

Therefore, length = 20 x 840 x 2.2 yards

Length = 36,960 yards

1 yard = 0.9144 meters

36,960 yards = 33,796 meters

### 19. A sheeting fabric having 30 tex in warp and 20 tex in weft, and having 40 x 30 ends and picks per centimetre respectively

1. 90 g/m2

2. 170 g/m2

3. 180 g/m2

4. 250 g/m2

Ans: 3

Given that

Ends per cm = 40

Picks per cm = 30

GSM = 0.1 [(N1 x n1)+ (N1 x n1)]

= 0.1 [(30 x 40) + (20 x 30)]

= 0.1 x 1800 = 180 g/m2

### 20. In an automatic loom

1. Weft break is repaired automatically.

2. The warp break is repaired automatically.

3. Exhausted weft bobbin is replaced automatically.

4. Exhausted warp bobbin is replaced automatically.

Ans: 3

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